A rock was dropped into a deep canyon and you hear the rock hit the bottom after 11.3 seconds.How deep is the canyon?
velocity of sound is 340m/s in air
gravity is 9.8m/s/s
i know that only two equations are involved in this problem, they are
d=Vit+1/2at^2 (Vi is initial velocity, since Vi equal to 0 the equation is just d=1/2at^20)
The Attempt at a Solution
this is what i did:
(340m/s x 11.3s)/2=1921m
i think about this answer but this doesnt make any sense, according to my answer the rock must be travel at the speed of sound.
by the way i divided by 2 because the rock need 5.65( 11.3/2) to reach the bottome and another 5.65 seconds for the sound to reach your ears. Total of 11.3 seconds
please help, im stuck here
thank you a lot