- #1

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## Homework Statement

Triple Integral (x^6e^y)dV bounded by z=1-y^2 z=0 x=-1 x=1

## The Attempt at a Solution

So I chose to try to integrate this in the order dydzdx

My bounds for the dy integral were from zero to (1-z)^(1/2)

my bounds for the dz integral were from 0 to 1

and my bounds for the dx integral were from -1 to 1.

I did the whole crazy integral and got 2/7 which my online thing is saying is wrong X_x doh...

Do these bounds look correct?