# Need help yet again

1. Oct 12, 2004

### Tanya Back

Hey Guys! I need ur help with this question, this question is like an incline with a pully..so we have puck which is on an incline surface, and the puck
( mass of 0.5455kg) is attached to a string which is attached to a pully, which also has a string attached to a mass of 0.05 kg. Acceleration is 0.34 m/2^2. The angle is 4.41.

A) Calculate the forces against the puck?

This wut i did-->
Ft= Force of tension
Fa= Forces the against the puck
Fnet= Ft - Fa

Since we don't have force of tesion, i used Fnet = Fg- Ft
Fnet = Fg- Ft
0.05x 0.34= 0.05x 9.8 - Ft
Ft= 0.47265

So then i used in this equation --> Fnet= Ft - Fa
Fnet= Ft - Fa
(0.5455)(0.34)= 0.47265- Fa

B) Should Ff be considered as a major force for your case?

Fn =mgcos4.4
5.3333 N
Fn= Force of gravity prependicular

Fg= 5.3459N ---> 0.5455 x 0.34

Then i did

a^2 + b^2 = c^2
a= Fn
c= Fg
b= force of gravity parallel

I solved for b and i got 0.3711 N
SO then i did Ff = Fa- Fg parallel
0.28242- 0.37115 = -0.08873 N

I got a negative force of firction :surprised ..so now i have no clue wut do to

I am sorre if some of you guys are confused, and plz tell me wut i am doing rite or wrong...this assignment is worth big marks anyways THANK U in advance.
Tanya

2. Oct 12, 2004