# Need help

1. Jan 22, 2008

### cc123

who can fill the brace:
-3,0,26,252,()
thanks a lot!

2. Jan 22, 2008

### HallsofIvy

Staff Emeritus
?? In what way? is there any reason that brace could not contain any integer? What are the conditions you are not telling us about?

3. Jan 22, 2008

### rohanprabhu

most probably it's some pointless IQ test where we go on filling in patterns and numbers and all that stuff..

4. Jan 22, 2008

### CRGreathouse

Whew. I get
$$\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144$$
There's no rounding needed since it's even.

5. Jan 22, 2008

### rohanprabhu

d00d seriously.. what did u just do??

6. Jan 22, 2008

### HallsofIvy

Staff Emeritus
Oh, well, of course!

7. Jan 22, 2008

### dodo

Can you change the first to -6, instead of -3?

8. Jan 23, 2008

### cc123

in any way i think.there are many answers if you can tell the reason.
to Dodo, if u change the first to -6,what is your answer?thank u!

9. Jan 23, 2008

### dodo

With a -6... is it ambiguous. It would be the sequence
$$2^2-10, \ \ \ \ \ \ 2^3-8, \ \ \ \ \ \ 2^5-6, \ \ \ \ \ \ 2^8-4$$​
so the next is $$2^n-2$$, and n depends on how you interpret the sequence of exponents: if it is Fibonacci, then n=11 for a value of 2046, if it is a quadratic, n=12 and you get 4094.