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Need help

  1. Jan 22, 2008 #1
    who can fill the brace:
    -3,0,26,252,()
    thanks a lot!
     
  2. jcsd
  3. Jan 22, 2008 #2

    HallsofIvy

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    ?? In what way? is there any reason that brace could not contain any integer? What are the conditions you are not telling us about?
     
  4. Jan 22, 2008 #3
    most probably it's some pointless IQ test where we go on filling in patterns and numbers and all that stuff..
     
  5. Jan 22, 2008 #4

    CRGreathouse

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    Whew. I get
    [tex]\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144[/tex]
    There's no rounding needed since it's even.
     
  6. Jan 22, 2008 #5
    d00d seriously.. what did u just do??
     
  7. Jan 22, 2008 #6

    HallsofIvy

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    Oh, well, of course!
     
  8. Jan 22, 2008 #7
    Can you change the first to -6, instead of -3?
     
  9. Jan 23, 2008 #8
    in any way i think.there are many answers if you can tell the reason.
    to Dodo, if u change the first to -6,what is your answer?thank u!
     
  10. Jan 23, 2008 #9
    With a -6... is it ambiguous. It would be the sequence
    [tex]2^2-10, \ \ \ \ \ \ 2^3-8, \ \ \ \ \ \ 2^5-6, \ \ \ \ \ \ 2^8-4[/tex]​
    so the next is [tex]2^n-2[/tex], and n depends on how you interpret the sequence of exponents: if it is Fibonacci, then n=11 for a value of 2046, if it is a quadratic, n=12 and you get 4094.
     
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