Slope of Secant Line at PQ

[jimen113]

I have not seen math in years and just started claculus last week.

Homework Statement

The point p(25,7) lies on the curve y=$$\sqrt{}x$$+2. Let Q be the point (x, $$\sqrt{}x$$+2).
Find the slope of the secant line PQ for the following values of x:
If x=25.1, the slope of PQ is:

Homework Equations

I

The Attempt at a Solution

I was using the formula : m$$_{}pq$$= x$$_{}2$$ -1 /X-1 and substituting x for 25.1 and then performed division.
Im new to the site and I'm getting used to the formatting so excuse my errors,

 

[mighty2000]

but here is my response to the forum post:

Hello!

First of all, congratulations on starting calculus! It can be a challenging subject, but with practice and determination, I am sure you will excel.

To find the slope of the secant line PQ, we need to use the slope formula: m = (y2-y1)/(x2-x1). In this case, our point P is (25,7) and our point Q is (x,√x+2). So, we can plug these values into the formula to get:

m = (√x+2-7)/(x-25)

Now, to find the slope when x = 25.1, we can simply substitute 25.1 for x in the formula:

m = (√25.1+2-7)/(25.1-25)

Simplifying this, we get:

m = (5.1/0.1)

Therefore, the slope of the secant line PQ when x = 25.1 is 51.

I hope this helps! Keep practicing and don't hesitate to ask for help if you get stuck on any other problems. Good luck!