- #1

ArmiAldi

- 3

- 0

1) Find the equation of the line tangent to the curve at the point

xy + y = 2 ; (1, 1) and i did this

xy + y = 2

y + xy' + y' = 0

xy' + y' = - y

y'(x + 1) = -y

y' = -y/(x + 1)

y' = -1/2

y- y_1 = m(x - x_1) and i hope so this is OK

but how can i do this one?

2) xy + x = 2 ; (1, 1) please help have to answer in 3 hours