Calculate Absorber Thickness: 4.1 x 4.2 Inch Paper Weighing 36 Grams

[vvbandit]

Heres the question, a piece of paper is 4.1 inch by 4.2 inch and weighs 36grams(it was a typo in the book it should be .36, but I am supposed to go with 36.) The question wants the absorber thickness, which is the density*distance in grams/centimeters^2

 

[The Bob]

So what have you done and what is the main problem?

The Bob (2004 ©)

 

[quicknote]

To calculate the absorber thickness, we first need to convert the measurements of the paper to centimeters. 4.1 inches is equivalent to 10.41 centimeters and 4.2 inches is equivalent to 10.67 centimeters.

Next, we need to convert the weight of the paper from grams to grams/centimeters^2. This can be done by dividing the weight (36 grams) by the area of the paper (10.41 cm x 10.67 cm = 110.9627 cm^2). This gives us a weight per unit area of approximately 0.325 grams/centimeters^2.

Finally, we can calculate the absorber thickness by dividing the weight per unit area by the density of the paper. The density of paper can vary, but for this calculation, we will assume a density of 1 gram/centimeter^3. Thus, the absorber thickness would be 0.325 grams/centimeters^2 divided by 1 gram/centimeter^3, which gives us a thickness of 0.325 centimeters.

In summary, the absorber thickness for a piece of paper measuring 4.1 inches by 4.2 inches and weighing 36 grams would be approximately 0.325 centimeters. However, it is important to note that this calculation is based on assumptions and the actual density of the paper may vary, resulting in a slightly different thickness.