A potter's wheel, with rotational inertia 6.40 kg * m^2, is spinning freely at 19.0 rpm. The potter drops a 2.80 kg lump of clay onto the wheel, where it sticks a distance of 47.0 cm from the rotation axis.
I know I need to use angular momentum here, but I am a little confused..
The Attempt at a Solution
conver to SI units:
19 rpm * (2 pi radians/1 revolution) * ( 1 minute / 60 seconds) = 1.99 radians
radius = 0.47 meters
mass = 2.8 kg
I know I need to use angular momentum: L = Iw
and i think this has to do with conservation of momentum but I need some direction.
so the total angular momentum needs to be the sum of the angular momentum before and after the lump is dropped on the wheel,
w(inital)mv^2 + Iw(final)= Iw
first term being the angular momentum before the drop so we can replace the moment of inertia by mv^2 since it is a disk
second term being after the lump is dropped on the disk
the sum of these is the total angular momentum, is this on the right approach?
something doesn't seem quite right to me..