A wingless fly of mass m sits on top of a platform of mass M supported by a spring of constant k. At time t the fly decides to jump upwards and by doing so, reaches a maximum altitude of 2d above the equilibrium point of the unloaded spring (i.e. the spring without the platform and fly). Assuming that the spring has no mass, find what is the maximum depth reached by the platform.(adsbygoogle = window.adsbygoogle || []).push({});

2. Relevant equations

F=-kx

3. The attempt at a solution

I have no idea how the fly jumping up a certain height has anything to do with the depth at which the spring originally was...the most simple answer I could come up with:

F = -kx

mg+MG = -kx

x = -g(m+M)/k

Thanks

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# Homework Help: Need some help Springs

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