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## Main Question or Discussion Point

Hello all,

I have a fellow grad student who is convinced that the differential cross section:

[tex] \frac{d\sigma}{d\Omega}[/tex]

is truly a ratio of differentials. That is you have an infinitesimal cross section divided by an infinitesimal solid angle.

I contend that when we write

[tex] \frac{d\sigma}{d\Omega}[/tex]

we really mean

[tex] \sigma(\Omega) [/tex] and that we only call it the differential cross section because the integral of the differential cross section over the physical range of the variable gives the total cross section.

I stated this along with the fact that the total cross section is simply a number. You sample an event (lets say pp->pp is the event in question) at different energies and record the number of particles that come out of the reaction at the energy. This gives you a number.

The derivative of the number with respect to any variable is zero. So the differential cross section- is not the derivative of the cross section.

He contends this is not true because when you do the "experiment" you have a finite width detector and this smears out the solid angle so it is no longer an infinitesimal.

Can anyone find a very clear discussion somewhere about this fact? Or maybe present one? Or am I simply wrong and it truly can be thought of as a ratio of differentials?

Thanks,

Ryan

I have a fellow grad student who is convinced that the differential cross section:

[tex] \frac{d\sigma}{d\Omega}[/tex]

is truly a ratio of differentials. That is you have an infinitesimal cross section divided by an infinitesimal solid angle.

I contend that when we write

[tex] \frac{d\sigma}{d\Omega}[/tex]

we really mean

[tex] \sigma(\Omega) [/tex] and that we only call it the differential cross section because the integral of the differential cross section over the physical range of the variable gives the total cross section.

I stated this along with the fact that the total cross section is simply a number. You sample an event (lets say pp->pp is the event in question) at different energies and record the number of particles that come out of the reaction at the energy. This gives you a number.

The derivative of the number with respect to any variable is zero. So the differential cross section- is not the derivative of the cross section.

He contends this is not true because when you do the "experiment" you have a finite width detector and this smears out the solid angle so it is no longer an infinitesimal.

Can anyone find a very clear discussion somewhere about this fact? Or maybe present one? Or am I simply wrong and it truly can be thought of as a ratio of differentials?

Thanks,

Ryan