- #1
Novus Dakota
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If the mass slides down the inclined plane fomr the top, what will the speed be when it reaches the bottom
so my equation is KE=1/2mv^2
so 281 J = 1/2 (5) v^2
Im blanking out on how to cancel out the square aaah thx
EDIT : I GOT IT THanks
so my equation is KE=1/2mv^2
so 281 J = 1/2 (5) v^2
Im blanking out on how to cancel out the square aaah thx
EDIT : I GOT IT THanks
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