# Need some serious math help

1. Apr 6, 2004

### travishillier

Need some serious math help ....

Heres teh question .....

A Parallelogram has a base lenght of 12cm. In order to increse teh area of teh paralleogram by 54cm(squared), the lenght of the base is increased by 2cm and the height is incresed by 3cm . Find the area of the original parallelogram.

The solution requires me to use fully defined variables, formula(s), all steps shown using good math form and concluding statements with appropriate units .

Any help is greatly appreaciated ... PLMK what ui can do to help me ...

Last edited: Apr 6, 2004
2. Apr 6, 2004

area of a parallelogram = b*h

area of "old" p-gram = b*h = 12h cm
area of "new" p-gram = (b+2 cm)(h+3 cm) = (12 cm + 2 cm)(h+3 cm) = (14 cm)(h+3 cm) = 14h cm + 42 cm^2

So, the area increased by 54 cm^2, so:

(area "new" p-gram) - (area "old" p-gram) = 54cm^2

14h cm + 42 cm^2 - 12h cm = 54cm^2
2h cm + 42 cm^2 = 54cm^2
2h cm = 12 cm^2
h = 6 cm

So, the original height is 6 cm.

Original formula: A=b*h=(12 cm)(6 cm) = 72 cm^2

And, just to check with the new area...

A=(b+2)(h+3)=(12 cm +2 cm)(6 cm + 3 cm)=(14 cm)(9 cm) = 126 cm^2

And make sure the difference is 54: 126 cm^2 - 72 cm^2 = 54cm^2

3. Apr 6, 2004

### travishillier

hey, thx alot for teh info on this question .. you could not of helped me any more ... thx a mill