Need to derive the distance formula from the acceleration due to gravity

1. Sep 13, 2005

Icedfire01

Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.

2. Sep 13, 2005

robphy

What facts or definitions do you have to start with? (Are you taking an algebra-based or calculus-based course?)

3. Sep 13, 2005

amcavoy

Start with acceleration, "a." You know that the second derivative of "a" is "s'', where "s" is the position. Integrate twice and adjust for the constants.

∫a dt = at+v0 = v

∫v dt = .5at2+v0t+s0 = s

Last edited: Sep 13, 2005