Need to derive the distance formula from the acceleration due to gravity

  • Thread starter Icedfire01
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  • #1
Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
 

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  • #2
robphy
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What facts or definitions do you have to start with? (Are you taking an algebra-based or calculus-based course?)
[By the way, post your question in only one thread.]
 
  • #3
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Start with acceleration, "a." You know that the second derivative of "a" is "s'', where "s" is the position. Integrate twice and adjust for the constants.

∫a dt = at+v0 = v

∫v dt = .5at2+v0t+s0 = s
 
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