1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Need to derive the distance formula from the acceleration due to gravity

  1. Sep 13, 2005 #1
    Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
     
  2. jcsd
  3. Sep 13, 2005 #2

    robphy

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    What facts or definitions do you have to start with? (Are you taking an algebra-based or calculus-based course?)
    [By the way, post your question in only one thread.]
     
  4. Sep 13, 2005 #3
    Start with acceleration, "a." You know that the second derivative of "a" is "s'', where "s" is the position. Integrate twice and adjust for the constants.

    ∫a dt = at+v0 = v

    ∫v dt = .5at2+v0t+s0 = s
     
    Last edited: Sep 13, 2005
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?