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Homework Help: Need to derive the distance formula from the acceleration due to gravity

  1. Sep 13, 2005 #1
    Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
  2. jcsd
  3. Sep 13, 2005 #2


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    What facts or definitions do you have to start with? (Are you taking an algebra-based or calculus-based course?)
    [By the way, post your question in only one thread.]
  4. Sep 13, 2005 #3
    Start with acceleration, "a." You know that the second derivative of "a" is "s'', where "s" is the position. Integrate twice and adjust for the constants.

    ∫a dt = at+v0 = v

    ∫v dt = .5at2+v0t+s0 = s
    Last edited: Sep 13, 2005
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