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Need to find the residue

  1. Dec 1, 2012 #1
    I need to find the residue of
    [tex]
    \frac{e^{2/z}}{1+e^z}
    [/tex]

    at z = [itex]\pi i[/itex]

    I've been scribbling over numerous papers trying to figure this out. So far I've tried to expand the denominator

    [tex]
    \frac{e^{2/z}}{(1-e^z + \frac{e^{2z}}{2!} - ...)}
    [/tex]

    I think maybe I've expanded that incorrectly, but I was thinking about pulling an [itex]e^z[/itex] out of the denom and multiplying the entire function [itex]f(z)[/itex] by the expanded 'leftovers', but I think that's incorrect too..
    [tex]
    \frac{e^{2/z}}{e^z(\frac{1}{e^z}-1+1-...)}
    [/tex]

    I feel like my steps are misguided because I can't seem to see where to go next.
     
    Last edited by a moderator: Feb 5, 2013
  2. jcsd
  3. Dec 1, 2012 #2

    Dick

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    Science Advisor
    Homework Helper

    Re: Residues

    You can find residues by solving limit problems. Do you know that way? And yes, you are expanding incorrectly. But that's not really the way to do it anyway.
     
    Last edited: Dec 1, 2012
  4. Dec 2, 2012 #3
    Re: Residues

    Would it need to be a L'Hopital statetgy? (I'm gonna try it). Also, I know this is the worst possible thing to say, according to a professor of mine, but I've gotten lazy and not practiced Taylor/Macluarin expansions in a while. I was under the impression that I could just expand 1/(1+x) and replace all the x's with [itex]e^x[/itex]. What did I do wrong in there?
     
  5. Dec 2, 2012 #4

    Dick

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    Science Advisor
    Homework Helper

    Re: Residues

    You can do that. You didn't do it right. What's the expansion of 1/(1+x)? But the expansion won't help you find the residue. Yes, write a limit and use l'Hopital.
     
  6. Dec 2, 2012 #5
    Re: Residues

    I know. Just looking to fill in memory lapses with my Calculus.

    Thanks for the guidance.
     
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