- #1
Mikey-D
- 11
- 0
First off, this isn't a homework question. I need a solution to the following in terms of [tex]\theta[/tex]. I don't have access to any math software, it's been a number of years since I've done any serious trig, and when I try to solve it on paper it turns into a cluster**** of confusion. If anyone can drop this into maple or something and grab me a solution, I'd be eternally grateful...
[tex]
\frac{d_1 Sin\theta}{Cos^2\theta} = - \frac{d_2 Sin(\theta+\phi)}{Cos^2 (\theta+\phi)}
[/tex]
Thanks!
[tex]
\frac{d_1 Sin\theta}{Cos^2\theta} = - \frac{d_2 Sin(\theta+\phi)}{Cos^2 (\theta+\phi)}
[/tex]
Thanks!