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Two beetles run across flat sand, starting at the same point. Beetle 1 runs 0.5m due east, then 0.80m at 30 degrees north of due east. Beetle 2 also makes two runs; the first is 1.6m at 40 degrees east of due north. What must be (a) the magnitude and (b) the direction of its second run if it is to end up at the new location of beetle 1?

40 degrees east of due north = 50 degrees

vector A = 0.5m

vector B = 0.8m

vector C = 1.6m

A = .5i + 0j

B = (.8cos(30))i + (.8sin(30))j

C = (1.6cos(50))i + (1.6sin(50))j

R = 2.35i + 1.78j

R = [2.35^2 + 1.78^2]^1/2 = 2.95m

arctan=(1.78/2.35)=37.14 degrees

Answer should be: (a) 0.84m (b) 79 degrees

What am I doing wrong here? Am I approaching it wrong?

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# Homework Help: Need Vector Help

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