My algebra's shocking so I'm not sure if I found the limit correctly... (sorry, I can't figure out this latex thing :grumpy: )(adsbygoogle = window.adsbygoogle || []).push({});

lim n tends to infinity of (sqrt(n))^-n

Using the rules of indices, I simplified it so that it became

n^(-n/2)

And then I used the log rule thing on it.

e^ lim (-n/2 * ln(n))

This is where I'm not sure: lim (-n/2 * ln(n))

I took the limit of the numerator (-n * ln(n)) to be infinity as n tends to infinity and the limit of the denominator would be 2. Infinity/2 is infinity so e^infinity is infinity...

Could someone please confirm or correct? Thanks :)

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# Need working checked for limits question

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