- #1

- 18

- 0

10. An electromagnetic radiation has a frequency of 5.00 x 10^14Hz.

b) Calculate its wavelength in water.

**Given: wavelength = 0.6 x 10^-6m or 600nm**

Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med})

n = 1.33 for water

Required: wavelength(med)Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med})

therefore wavelength(vac) = (n)(wavelength{med}) and

wavelength(med) = wavelength(vac)/n

Solution: wavelength(med) = (0.6 x 10^-6m)/1.33= 4.51 x 10^-7 or 451 nm

Now I get looking at this and I'm not sure if that's exactly how I go about doing this or if this is what I'm supposed to do for finding the index of refraction (which comes later) Please help, my brain is fried.