- #1

calculus_jy

- 56

- 0

i can find that [tex]\Delta v^2 = 2xlnx[/tex] and since it is given that when [tex]t = 0, x = 1,v = 0[/tex]

[tex]\therefore v^2 = 2xlnx[/tex]

however i have been asked to prove [tex]v > 0 \; when \;t > 0[/tex] and i have no idea how to explain it in mathematcial terms, can anyone please give any suggestion?