given acceleration [tex]a = 1 + ln x[/tex](adsbygoogle = window.adsbygoogle || []).push({});

i can find that [tex]\Delta v^2 = 2xlnx[/tex] and since it is given that when [tex]t = 0, x = 1,v = 0[/tex]

[tex]\therefore v^2 = 2xlnx[/tex]

however i have been asked to prove [tex]v > 0 \; when \;t > 0[/tex] and i have no idea how to explain it in mathematcial terms, can anyone please give any suggestion?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Negative and positive

**Physics Forums | Science Articles, Homework Help, Discussion**