given acceleration [tex]a = 1 + ln x[/tex](adsbygoogle = window.adsbygoogle || []).push({});

i can find that [tex]\Delta v^2 = 2xlnx[/tex] and since it is given that when [tex]t = 0, x = 1,v = 0[/tex]

[tex]\therefore v^2 = 2xlnx[/tex]

however i have been asked to prove [tex]v > 0 \; when \;t > 0[/tex] and i have no idea how to explain it in mathematcial terms, can anyone please give any suggestion?

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# Negative and positive

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