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Negative energies.

  1. Aug 16, 2007 #1
    Hi, let be a Hamiltonian so its energies satisfy E(n)=-E(-n) for every n >0

    then my question is does this imply certain symmetry of potential ?? i belive that V(x)=-V(-x) so in absolute value positive and negative energies have the same value.
  2. jcsd
  3. Aug 16, 2007 #2
    I assume that by n you mean the quantum state number so that n=0 is the ground state. In that case, what does the negative number in E(-n) mean?
  4. Aug 17, 2007 #3
    Here 'n' is some kind of label for the Energy levels for example:

    E_{-2} = -0.6784356

    E_{-1} = -0.000456

    (if n is negative this means that energies will be negatives)

    E_{1} = 1.23456

    E_{2} =4.5676868

    (if n is positive energies will be positive)

    E_{0} = 0.4 (there is no ground state since if there are negative energies this means that operator H is 'unbounded' )
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