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If e=mc^2, then (e/m)1/2= either +c or -c. What is the physical meaning of minus c?

- Thread starter renerob
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- #1

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If e=mc^2, then (e/m)1/2= either +c or -c. What is the physical meaning of minus c?

- #2

Matterwave

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e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s.

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Nabeshin

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Precisely. Imagine the equation like this:e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s.

[tex]E=m(2)^2[/tex]

[tex] 2=\pm \sqrt{\frac{E}{m}} [/tex]

Hope this clarifies.

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