- #1
Tanishq Nandan
- 122
- 5
Homework Statement
Homework Equations
Snell's Law:
n1sin(i)=n2sin(r)
Critical angle=sininverse(n1/n2) [**only works when n2>n1]
If a light beam is incident at an interface of 2 mediums(with r.i n1 and n2) at an angle greater than the critical angle,the interface acts as a mirror,reflecting the entire beam.
The Attempt at a Solution
I thought of it in terms of critical angle,and saw that according to the formula,critical angle's coming out to be some negative value.Doesn't this mean that any angle of incidence greater than that(which is practically every possible light ray) will have i>critical angle and undergo reflection??
So,I thought option C to be correct.
However,answer's A.
Help appreciated.