K the question is 3^x^2+20=(1/27)^3x(adsbygoogle = window.adsbygoogle || []).push({});

well I got 3^x^2+20=(3^-3)^3x

the exponents make a quadratic function so i just set it = to 0 and factored to solve for x but this is what i got (x+4)(x+5) this means x=-4, or -5 but doesnt that mean there is no solution? We are not doing Log yet.

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# Homework Help: Negative Solutions for x?

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