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Mathematics
General Math
Nested expressions as compositions of functions?
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[QUOTE="fresh_42, post: 6275613, member: 572553"] You're right, what a stupid mistake me made. We would need an additional operator ##R_x\, : \,p(x)\longrightarrow p(x)\cdot x## to increase the powers of ##x## - just as many as there are (ring) operations: addition, scalar multiplication and normal multiplication. We could define ##R_{q(x)}(p(x))=p(x)\cdot q(x)## but that would overload the index. [/QUOTE]
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Mathematics
General Math
Nested expressions as compositions of functions?
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