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Net Capacitance

  • #1
1,137
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Hi again!!!

I got stuck in this question (Pic), the original question is the fig. 1. I then arranged the charges on the plates (fig 2) and then separated the plates to form three capacitors. Now I just don’t know what the capacitance will be and how to find it!!!
First I thought to ignore the two plates at 2 ends. Then the two capacitors on right will be in parallal and their resultant in series with the last one… then answer comes out to be 2C/3 … which is wrong!!!
According to the book’s answer, all three capacitors will be in series, to get capacitance as C/3 …
Please tell me how are three capacitors in series, and can I really ignore the end plates!!!!
 

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  • #2
1,137
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Please someone help!!!!
 
  • #3
ehild
Homework Helper
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They are not in series. Your equivalent circuit on the right is correct. Between which points do you need the resultant capacitance?

ehild
 
  • #4
1,137
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No, I am telling you they are in series because the net capacitance comes out to be (acc. to book) C/3
 
  • #5
1,137
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some help?
 

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