A) Determine the net force on charge 1.
B) What is the net electric field acting on charge 1?
The Attempt at a Solution
Let North and East be positive.
Because of symmetry, F21 = F31
F2 = F3
F2 = (9.0x109)(2.0x10-5(3.0x10-5) / (2.0m)2
F2 = 1.35N
Fnet = √1.35N2 + 1.35N2
Fnet = 1.909N
Fnet = 2N
For the angle of the electric force:
tan-1 = 2/2
therefore the net electric force on charge 1 is 2N [N 45º E].
Let right and up be positive.
Because of symmetry,
r = √22 + 22
Enet = 2E1cos45º
Enet = 2(kq1 / r2 cos45º
Enet = 2(9.0x109)(3.0x10-5) / (2√2)2 cos45º
Enet = 47729.7 N/C
Enet = 4.7 x104 N/C
Any input is appreciated as I still am not completely confident that I am doing these questions right. Thanks
19.4 KB Views: 319