Consider 3 force vectors F1, F2, and F3. The vector F1 has magnitude F1 = 55N and direction θ = 41°; the vector F2 has magnitude F2 = 20N and direction θ = - 140°; and the vector F3 has magnitude F3 = 17N and direction θ = 140°. All the direction angles θ are measured from the positive x axis: counter-clockwise for θ > 0 and clockwise forr θ < 0. A. What is the magnitude F or the net force vector F = F1+F2+F3? Answer in units of N. B. What is the direction of the net force vector F? State your answer as an angle θ between -180° and +180°. Answer in units of °. Horizontal: F*sin(θ) = x Vertical F*cos(θ) = y I found the x resultants to be 10.93 + 12.85 + 36.08 = 59.86 y resultants: 13.0227 + 41.50 + 15.32 = 69.8427 Then I added them and got 129.70745, but that is wrong. Please help me solve this question, I have no idea how to do it.