A 10 kg sled is pulled at 35 degrees east of north with 100 N. There is a force of 150 N due east. And a friction force of 50 N. What is the acceleration of the sled, and its direction?(adsbygoogle = window.adsbygoogle || []).push({});

So I basically added up all the forces in the x direction, and the y direction, and used the pythagorean theorem to get the net force, and divided it by the mass to get the acceleration. But somehow, I don't get the right answer, which is17.3 m/s^2 at 68.5 degrees east of north.

My work:

Net x force = cos(55)(100) + 150 - 50 =157.36 N

Net y force = sin(55)(100) =81.9 N

tan (x) = 81.9/157.36; x =27.5 degrees

square root of (157.36^2 + 81.9 ^2) =177.4 N; 17.7 m/s^2

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# Homework Help: Net force on a sled?

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