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Net Ionic equation

  1. Feb 21, 2008 #1
    Can anyone help me through this net ionic equation problem?

    Pb(ClO4)2 (aq) +NaI (aq) -> PbI2 (s) + NaClO4 (aq)
     
  2. jcsd
  3. Feb 22, 2008 #2
    Pb+2 + ClO4- + Na+ + I- -> PbI2 (s) + Na+ + ClO4-

    ClO4- and Na+ cancel out on both sides of the equation, so you're left with

    Pb+2 + I- -> PbI2 (s)
     
  4. Feb 22, 2008 #3

    chemisttree

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    Just make sure that you have the same number of Pb, ClO4, Na and I on both sides of the equation. In your example above, there is one I on the left and two on the right, for example. Same goes for ClO4....

    Snazzy, check your work before you post.
     
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