1. The problem statement, all variables and given/known data Calculate the net torque about the axle of the wheel shown in https://jigsaw.vitalsource.com/books/9781269392464/content/id/ch08fig39 [Broken]. Assume that a friction torque of 0.40 m · N opposes the motion. Where F=18N (in photo). The picture is here: http://www.webassign.net/giancoli/8-39alt.gif 2. Relevant equations τ (tau) = rF 3. The attempt at a solution Direction of the positive torque: counterclockwise direction T1 = 28N*24cm = 6.72 N-m T2 = -35N*12cm = -4.2 N-m T3 = -18N*24cm = -4.32 N-m Now you add all these torques 6.72 N-m -4.2 N-m -4.32 N-m = -1.8 N-m Since I know the direction of rotation is clockwise, I added the friction torque to that result in the opposite direction: -1.8 N-m +0.40 N-m = -1.4 N-m (clockwise) This is the only way I was able to get the right answer. However, my first try was using -35Nsin135. Why do I not have to take the component of F in this example?