a man pulls a 10 kg box up an incline at a constant speed to a vertical height of 5 m. what is the net work being done?
The Attempt at a Solution
i know in the plane perpendicular to the surface there is no net work done because all the forward forces (the pull) cancel out the backward forces (friction and gravity). however, isnt there a net force being done by gravity because he rose the box up 5 meters?
would the answer be (5m)(9.8)(10kg) = 490 J
or would it be 0 J because its not accelerating at all? whihc one is correct? thanks.