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Neutral Buoyancy of a fish

  1. Nov 29, 2008 #1
    1. The problem statement, all variables and given/known data

    The average density of the body of a fish is 1147.0 kg/m3. To keep from sinking, fish have an air bladder filled with air. If the density of air is 1.28 kg/m3, what percentage of a fish's body must be filled with air to be neutrally buoyant? (Note: Enter your percentage without a unit attached.)


    2. Relevant equations

    /rho avg = Total mass of object / Total volume of object
    /rho avg = 1000 kg/m^3


    3. The attempt at a solution

    /rho avg = Mo / Vo (Total mass/ divided by total volume)

    Mo = Ma + Mf (Ma= mass of air and Mf= mass of fish)

    Ma= 1.28Va (density of air x volume of air)

    Mf = 1147Vf (density of fish x volume of fish)

    Now subsituting all the equations together I get...

    /rho avg = 1000 = (1.28Va + 1147 (Vo-Va)) / Vo

    and isolating for Va/ Vo = .128 x100% = 12.8 %

    I also did this to get get Ma / Mo = 0.016% ... but neither answer is right :S. Can anyone tell me what I did wrong, or whether their answer is wrong? Its much appreciated thanks!
     
  2. jcsd
  3. Nov 29, 2008 #2

    epenguin

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    I get pretty close to you, about 13%.

    I think your (Vo-Va) is wrong and seems to be assuming the tissues of the fish are compressed. Not so, the tissues are incompressible and the fish actually has to get bigger!

    What is the right answer supposed to be?
     
  4. Nov 29, 2008 #3
    Well with the (Vo - Va) thing... i forgot to show my steps with that. Basically orginially its 1147 times the volume of the fish... and I assumed that volume of fish plus volume of air is equal to volume of object. Thus Vo = Va + Vf and I isolated for Vf and subsituted it into the equation.

    As for the answer I am unsure, it is an online quiz thing... have 10 attempts to get the answer. So far I tried like those few ways.
     
  5. Nov 29, 2008 #4
    The answer was 14.7%. Apparently it wanted the volume of the air to the volume of the fish, not relative to the total volume. Therefore instead of substituting to get rid of Vf I'd need to substitute to get rid of Vo and Isolate for Va/ Vf.

    Thanks for the help though!
     
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