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Neutral pions

  1. Feb 18, 2013 #1
    So apparently a neutral pion is a superposition of [itex]u\bar{u}[/itex] and [itex]d\bar{d}[/itex]. I'm having trouble understanding what this means. I have no problem understanding how the decay products of some scattering experiment could be a superposition of these two states, but how can we treat this superposition as a single particle? And how would you draw the feynman diagram for some process involving a neutral pion?
  2. jcsd
  3. Feb 18, 2013 #2

    Simon Bridge

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    The neutral pions are decay products from scattering.
    There are plenty of examples online of Feynman diagrams involving pions.
  4. Feb 19, 2013 #3
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