# Neutralization calculations

1. May 16, 2006

### Aya

A student obtains 25.00 mL of an HCl solution of unknown concentration. Upon titration, 21.35 mL of 0.1200 M NaOH are required for neutralization. Determine the concentration of the HCl solution.

the capital M is molar mass right? but i thught that was constant so how can it be 0.1200 M NaOH? or do they mean m for mols

so the first thing you need to do is write the equation

NaOH + HCL = NaCl + H2O

using the mol ration, the number of mols will be the same for every thing elce
soo... now what?

Last edited: May 16, 2006
2. May 16, 2006

M stands for the concentration of the solution. It is equivalent to $$moldm^{-3}$$ or $$mol/litre$$.