Neutralization calculations

  • Thread starter Aya
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  • #1
Aya
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A student obtains 25.00 mL of an HCl solution of unknown concentration. Upon titration, 21.35 mL of 0.1200 M NaOH are required for neutralization. Determine the concentration of the HCl solution.

the capital M is molar mass right? but i thught that was constant so how can it be 0.1200 M NaOH? :confused: or do they mean m for mols :confused:

so the first thing you need to do is write the equation

NaOH + HCL = NaCl + H2O

using the mol ration, the number of mols will be the same for every thing elce
soo... now what?
 
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Answers and Replies

  • #2
172
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M stands for the concentration of the solution. It is equivalent to [tex]moldm^{-3}[/tex] or [tex]mol/litre[/tex].
 

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