Neutron scattering

1. Jun 8, 2006

NEWO

hi,

in neutron scattering, if the lowest kinetic energy of a neutron is increased by a factor of 2, how do you work out the number of peaks produced?

I have worked out the lowest kinetic energy for a beta-brass CuZn to be 2.37meV using

$$E=\frac{\hbar^{2}k^{2}}{2m}[\tex] where [tex]k=\frac{2\pi}{\lambda}[\tex] and [tex]\lambda=2d\sin\theta[\tex] I would appreciate any help on this. thanks newo 2. Jun 8, 2006 NEWO hmm my latex doesn't seem to work here, dunno why, can you get the gist of it??? 3. Jun 8, 2006 Hootenanny Staff Emeritus You need to swap the back-slashes to forward slashes like this (without the spaces) [ /tex ] As for your question, how does this; Relate to n? Remember than for the maximum n $\Rightarrow \sin\theta = 1$, also note that the number of peaks = n+1 Last edited: Jun 8, 2006 4. Jun 8, 2006 NEWO ahhh so [tex] \lambda=nd\sin\theta$$

or am I missing something

5. Jun 8, 2006

Hootenanny

Staff Emeritus
Almost, I believe it is;

$$\lambda = \frac{d\sin\theta}{n} \Leftrightarrow n = \frac{d\sin\theta}{\lambda}$$

Can you see what happens if you increase the kinetic energy of the particle?

6. Jun 8, 2006

NEWO

yeah as the energy increases the number of peaks increases also

thanks for your help it is much appreciated

7. Jun 8, 2006

Hootenanny

Staff Emeritus
Sounds good to me. My pleasure