- #1
NEWO
- 95
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hi,
in neutron scattering, if the lowest kinetic energy of a neutron is increased by a factor of 2, how do you work out the number of peaks produced?
I have worked out the lowest kinetic energy for a beta-brass CuZn to be 2.37meV using
[tex]E=\frac{\hbar^{2}k^{2}}{2m}[\tex] where
[tex]k=\frac{2\pi}{\lambda}[\tex] and
[tex]\lambda=2d\sin\theta[\tex]
I would appreciate any help on this.
thanks
newo
in neutron scattering, if the lowest kinetic energy of a neutron is increased by a factor of 2, how do you work out the number of peaks produced?
I have worked out the lowest kinetic energy for a beta-brass CuZn to be 2.37meV using
[tex]E=\frac{\hbar^{2}k^{2}}{2m}[\tex] where
[tex]k=\frac{2\pi}{\lambda}[\tex] and
[tex]\lambda=2d\sin\theta[\tex]
I would appreciate any help on this.
thanks
newo