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## Homework Statement

What is the kinetic energy given to the proton in the decay of the neutron when a) the electron has negligibly small kinetic energy; b)antineutrino has small negiligibly energy

## Homework Equations

The decay reaction

[tex] n\Rightarrow p+e^{-}+\bar{\nu}[/tex]

now I try to work out the Q-value (I assume that neutron is at rest)

[tex] m_{n}c^2=m_{p}c^2+T_{p}+m_{e}c^2+T_{e}+m_{\bar{nu}}c^2+T_{\bar{\nu}}[/tex]

then movin all the therms with c^2 to the left side I get

[tex](m_{n}-m_{p}-m_{e}-m_{\bar{\nu}})c^2=T_{p}+T_{\bar{\nu}}[/tex]

so

[tex] Q=T_{p}+T_{\bar{\nu}}[/tex]

the Q value can be easily calculated but what with the other kinetic energies on the right side? It this correct?