(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is moving with velocity √3 m/s towards right. The velocity of end B when rod makes an angle of 60^{o}with the ground.

2. Relevant equations

3. The attempt at a solution

I assumed that at any instant the distance of A from block is x and distance of B from ground is y. The length of rod is l.

l^2=x^2+y^2

Differentiating with respect to time.

0=2x(dx/dt)+2y(dy/dt)

y=xtan(60^{o})

dx/dt=√3 m/s

Solving, i get

(dy/dt)=-3 m/s

But that's not correct, the answer says its 2 m/s. I don't seem to get where i am wrong.

Any help is appreciated.

Thanks!

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# Homework Help: Newton Laws of motion question

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