How Much Force Stopped the Diver Underwater?

[plqaokws]

Homework Statement

A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?

Homework Equations

Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?

The Attempt at a Solution

i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.

 

[FedEx]

Homework Statement

A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?

Homework Equations

Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?

The Attempt at a Solution

i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.

This will not work as the acc is not equal to -g. You have the velocity when the body touches the water surface. This is the initial velocity. Now the final velocity is zero.And the distance is 3m. So by v^2-u^2=2ad.You can find a, and then you can apply f=ma.Here v is the final velocity and u is the initial velocity.

 

[m2003]

I would like to clarify that Newton's 2nd Law states that the net force acting on an object is equal to the product of its mass and acceleration (F=ma). In this scenario, the diver's initial velocity, final velocity, and distance traveled are not given, so we cannot calculate the force using the equation F=ma. We also need to consider other factors, such as the resistance of the water and the diver's own buoyancy. Therefore, it is not possible to determine the exact amount of force that brought the diver to a stop without more information. However, we can say that the net force acting on the diver was opposite to his initial direction of motion and was enough to decelerate him to a stop in 3 meters.