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Newton's 2nd law/kinematics

  1. Sep 21, 2007 #1
    1. The problem statement, all variables and given/known data

    A baggage handler drops your 9.10kg suitcase onto a conveyor belt running at 2.90m/s . The materials are such that ms= 0.560 and mk= 0.150.

    How far is your suitcase dragged before it is riding smoothly on the belt? (in meters)

    2. Relevant equations

    fk = mk times normal force
    fs = ms times normal force
    and kinematic equations

    3. The attempt at a solution

    forces acting on the suitcase:

    normal force in upwards y direction = 89.2 N
    weight (mg) in downwards y direction = -89.2 N
    static friction or kinetic friction?? towards the left x direction

    positive velocity of the conveyor belt towards the right x direction = 2.90m/s
  2. jcsd
  3. Sep 21, 2007 #2

    Chi Meson

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    Static friction is the force that will accelerate the suitcase until it reaches the final velocity of the conveyor belt.
  4. Oct 23, 2007 #3
    Actually you have to use the kinetic friction coefficient.

    First, find the acceleration of the bag. Hint (a = mk * g)

    Then use your kinematic equation to solve for X or the position. I used: Vi^2 = Vf^2 + 2a*x. Keep in mind that the initial velocity or Vi is 0.

    Hope that helps.
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