Newton's 2nd law/kinematics

1. Sep 21, 2007

nerdgirl909

1. The problem statement, all variables and given/known data

A baggage handler drops your 9.10kg suitcase onto a conveyor belt running at 2.90m/s . The materials are such that ms= 0.560 and mk= 0.150.

How far is your suitcase dragged before it is riding smoothly on the belt? (in meters)

2. Relevant equations

fk = mk times normal force
fs = ms times normal force
and kinematic equations

3. The attempt at a solution

forces acting on the suitcase:

normal force in upwards y direction = 89.2 N
weight (mg) in downwards y direction = -89.2 N
static friction or kinetic friction?? towards the left x direction

...
positive velocity of the conveyor belt towards the right x direction = 2.90m/s

2. Sep 21, 2007

Chi Meson

Static friction is the force that will accelerate the suitcase until it reaches the final velocity of the conveyor belt.

3. Oct 23, 2007

jedi_david

Actually you have to use the kinetic friction coefficient.

First, find the acceleration of the bag. Hint (a = mk * g)

Then use your kinematic equation to solve for X or the position. I used: Vi^2 = Vf^2 + 2a*x. Keep in mind that the initial velocity or Vi is 0.

Hope that helps.