Newton's 2nd Law: Determine Force Magnitude (6.05 N, 6.1 m/s, 2.5 kg)

[liamtcarroll]

A 2.5 kg mass accelerates at 6.1 m/s
in adirection 37◦north of east. One of the two
forces acting on the mass has a magnitude of
6.05 N and is directed north.
Determine the magnitude of the second
force.
Answer in units of N
I know you have to break it up into multiple components, but otherwise i don't have a clue of what to do

 

[aralbrec]

If a mass accelerates in a certain direction, the net force applied to the mass must act in the same direction.

F = ma is a vector equation.

 

[bsbs]

ya, key word here is net force, two forces accelerating at 6.1m/s/s, one of which was given, just get the N and magnitude correct for the other.

if you are the marker for my exam, i think i'll be gone! amended the units for acceleration...hahaha

 

[aralbrec]

Just pointing out the acceleration is 6.1 m/s². It was beginning to bug me now that I've seen it in multiple threads :-)

 

[Nickie]

.

According to Newton's Second Law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this scenario, the mass is 2.5 kg and the acceleration is 6.1 m/s^2 in a direction 37 degrees north of east. This means that the net force acting on the object is given by:

Fnet = m * a
Fnet = (2.5 kg) * (6.1 m/s^2)
Fnet = 15.25 N

Since one of the two forces acting on the object has a magnitude of 6.05 N and is directed north, we can use vector addition to determine the magnitude of the second force. Since the direction of the second force is not specified, we can assume it is in the east direction, opposite to the direction of the acceleration.

Using the Pythagorean theorem, we can find the magnitude of the second force as:

F2^2 = Fnet^2 - F1^2
F2^2 = (15.25 N)^2 - (6.05 N)^2
F2^2 = 232.56 N^2 - 36.6 N^2
F2^2 = 195.96 N^2
F2 = 14 N

Therefore, the magnitude of the second force is approximately 14 N.