• Support PF! Buy your school textbooks, materials and every day products Here!

Newton's 2nd law

  • Thread starter kgood5885
  • Start date
  • #1
2
0
I figured out the horizontal friction force, Fpx to be 55.11 N and the normal force exerted vertically to be 190.8 N. And the other info given is F = 84 the lawn mower has a mass of 13 kg and moves at a constant speed. The lawn mower is at an angle of 49 degrees to the horizontal. I need to determine the force the person must exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.0 seconds (assuming the same retarding force).
Do I use the equation 84 cos 49 + F (friciton) = ma??? Or how do I set up this problem?
 

Answers and Replies

  • #2
lightgrav
Homework Helper
1,248
30
If the person's Force is along a 49 degree handle
(while the lawn mower itself is on level?)
the person's force will increase the N required,
and might increase the friction Force.

Does your friction stay at 84 cos(49) ?
then get Fx_extra = ma_x
 

Related Threads for: Newton's 2nd law

  • Last Post
Replies
8
Views
884
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
15
Views
3K
  • Last Post
Replies
17
Views
8K
  • Last Post
Replies
11
Views
2K
  • Last Post
Replies
2
Views
1K
Top