1. The problem statement, all variables and given/known data The 20.0 kg box is being pushed with a 45.0N Force acting at an angle of 25.0*. The coefficient of kinetic friction on this surface is 0.150. Find the acceleration 2. Relevant equations F=ma Fy=0 Fx=0 3. The attempt at a solution So I attempted this so far (sum)Fy=0 Py+Fn-Fg=0 Fn=Fg-Py Fn=(20.0kgx9.81m/s^2)-45.0Nsin335* Fn=215.217822N I tried to go and do sum of all the forces on the x axis but there's no point because we already have Ffk and Px.......... So now do I go ahead and put all of the forces in for Sum of F in (sum)F=ma and solve for a? as in would I do Fx-Fg+Fn-Ffk=ma???