1. The problem statement, all variables and given/known data Two crates, of mass 80 kg and 210 kg, are in contact and at rest on a horizontal surface (Fig. 5-26). A 750 N force is exerted on the 80 kg crate. The coefficient of kinetic friction is 0.21. (a) Calculate the acceleration of the system. .53 m/s2 (to the right) [Note: This Answer is Correct] (b) Calculate the force that each crate exerts on the other. _________ N (c) With the crates reversed, calculate the force that each crate exerts on the other . _________ N 2. Relevant equations Ff= Mk(Normal Force) F=m(acceleration) 3. The attempt at a solution I did A, and I got .53, but I can't get B. I guess I just don't understand how to do it. I tried to calculate the force that Crate 1 exerts on Crate 2. I tried this but I got the wrong answer it says: Fy(net)=m(a)=Fa-Ff Ff=.21(Normal) Normal=Fg=9.8(mass)=9.8(80)=784 Ff=.21(784) Ff=164.64 Fy(net)= 80(.53)=Fa-164.64 Fa=207 It says that I'm wrong. :( I also can't get C...I don't even understand how to begin that one though.