1. The problem statement, all variables and given/known data A 245 kg motorcyle & rider can produce an acceleration of 3.50 m/s sq while travelling at 25 m/s. At that speed, the forces resisting motion (friction & air) total 400 N. What force does the motorcycle exert backward to produce it's acceleration? 2. Relevant equations Force = mass x acceleration + Friction motion 3. The attempt at a solution Fnet = (m x a) + Ffr = (245 x 3.5) + 400N = 1257.5N This needs a 2nd look. I'm not sure if the speed matters since we have mass and acceleration values. Please take a look, I'll stand by.