(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a grocery cart is being oused with a force of 450 N at an angel of 30degree to the horizontal. if the mass of the cart and groceries is 42kg.

a) calculate the force of friction if the coeffcient of friction is 0.60.

b) determine the acclecration of the cart.

2. Relevant equations

a) it is the 30 degree angel from the handle to the cart.

but i dont understand why you need to do 450sin(30) and add it by Fn=412.02N

3. The attempt at a solution

Ff= muFn

450sin (30)= 225N

Fn=mg

Fn= (42)(9.81)

= 412.02N

Fn= 225N + 412.02N

Fn= 637.02N

ff= 637.02N * 0.60

= 3.8 x 10^2 N

i got the answer but why do u need to find the vertical component and add it to Fn . what does the vertical component represent? and why does this give you FN?

please help me :-)

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# Newtons law - cart question

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