A cup of coffee at 174 degrees is poured into a mug and left in a room at 76 degrees. After 5 minutes, the coffee is 134 degrees. Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt = k(T-76)(adsbygoogle = window.adsbygoogle || []).push({});

here's what i done:

[tex]y(0) = 98e^{kt}[/tex]

y(5) = 134-76 = 58, so...

98e^{5k} = 58

k = -0.104904

[tex]y(15) = 98*e^{15*-0.104904} + 76[/tex]

and got 159.8448 which is wrong. anyone know where i went wrong?

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# Homework Help: Newton's Law of Cooling on cup of coffee

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