at t=0; thermometer reading (x) =80 F (taken outside where the air temp is 20 F)
at t=3; x=42 F
then the thermometer is brought inside where the air is at 80 F.
at t=10; x=71 F
When was the thermometer brought indoors?
temp=ambient temperature; x= present temp of the body
x - temp=Ce-kt
The Attempt at a Solution
first I get the value of k: t=0; x=80
x=60e-kt +20; t=3;x=42
Now, when brought inside:
at t=0, x=??
And I am currently stuck up in here. If answered, could someone explain how does it happen? Thanks in advance!