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Newtons Law Of Motion Problem
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[QUOTE="rajumahtora, post: 4578519, member: 494650"] To Admin - This is not my homework, My teacher solved it but I am trying to solve this problem using other methods. If I posted this in wrong group, please message me and I will Post this in correct corner. Problem - To find acceleration in both blocks sliding on smooth surface,string and pulley is frictionless and massless. Refer to diagram below.Use g = 9.8 m/s2 [ATTACH=full]165571[/ATTACH] My Solution - Free Body Diagram Of Block of mass M kg - [ATTACH=full]165572[/ATTACH] The Equation of forces in Y axis is 9.8M - Tsinα = Macosα ...eq(1) The Equation of forces in X axis is Tcosα = MAsinα ...eq(2) Free Body Diagra of Block of Mass N kg - [ATTACH=full]165573[/ATTACH] The Equation of forces in Y axis is Tsinβ - 9.8N = Nasinβ ...eq(3) The Equation of forces in X axis is Tcosβ = Na.cosβ ...eq(4) Now, after simultaneously solving eq(1) and eq(3), I am getting wrong answer Now, eq(4) is tell that T = Na which is not possible. [U]I guess I missed Normal Reaction Force but how to use it in equation[/U] [/QUOTE]
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Newtons Law Of Motion Problem
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