Acceleration of 3.8kg Object: 110.58 m/s2, 28.66°

[wallace13]

Only two forces act on an object (mass= 3.8 kg). One force is pointing east with 40 N. The other has a force of 75.0 N at a 45 degree angle. Find the magnitude and direction (relative to the x-axis) of the acceleration of the object.



pythagorean theorum
tan O= opp/adj



x y
53.03 53.03 < ---- found using 75sin45
40 0

= 97.03, 53.03 <--- resultant

pythagorean theorum with resultants = 110.58m/s
angle from tangent= 28.66 degrees

 

[alphysicist]

Hi wallace13,

Only two forces act on an object (mass= 3.8 kg). One force is pointing east with 40 N. The other has a force of 75.0 N at a 45 degree angle. Find the magnitude and direction (relative to the x-axis) of the acceleration of the object.



pythagorean theorum
tan O= opp/adj



x y
53.03 53.03 < ---- found using 75sin45
40 0

= 97.03, 53.03 <--- resultant

I believe that the 97.03 is incorrect.

 

[baba89]

Therefore, the magnitude of the acceleration of the object is 110.58 m/s^2 and the direction is 28.66 degrees relative to the x-axis. This acceleration is a result of the two forces acting on the object, with a net force of 115 N (40 N + 75 N). As a scientist, it is important to analyze and understand the forces acting on an object in order to accurately predict its acceleration and movement.