A 62-kg ice skater pushes off his partner and accelerates backwards at 1.8m/s2. If the partner accelerates in the opposite direction at 2.1m/s2, what is the mass of the other skater? Assume that frictional forces are negligible.
The Attempt at a Solution
Okay so I found the force the 62kg ice skater exerted. I subtracted the two accelerations and arrived at a -0.3 m/s^2 acceleration from the 62kg ice skater. So I plugged in:
F = (62kg)(-0.3m/s^2)
So the force exerted by the 62kg person is -18.6N. I don't really know where to go from there? I played around with the equation a bit but I can't seem to get anything remotely close to figuring the mass out of the second skater.
Like I'll put the equation as F+18.6N = (m)(0.3m/s^2) But then I'll have two unknowns but not two equations so it just doesn't work out.